2[k-(2k+12)+9]=2(k+3)

Solution for 2[k-(2k+12)+9]=2(k+3) equation:

Simplifying
2[k + -1(2k + 12) + 9] = 2(k + 3)

Reorder the terms:
2[k + -1(12 + 2k) + 9] = 2(k + 3)
2[k + (12 * -1 + 2k * -1) + 9] = 2(k + 3)
2[k + (-12 + -2k) + 9] = 2(k + 3)

Reorder the terms:
2[-12 + 9 + k + -2k] = 2(k + 3)

Combine like terms: -12 + 9 = -3
2[-3 + k + -2k] = 2(k + 3)

Combine like terms: k + -2k = -1k
2[-3 + -1k] = 2(k + 3)
[-3 * 2 + -1k * 2] = 2(k + 3)
[-6 + -2k] = 2(k + 3)

Reorder the terms:
-6 + -2k = 2(3 + k)
-6 + -2k = (3 * 2 + k * 2)
-6 + -2k = (6 + 2k)

Solving
-6 + -2k = 6 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-6 + -2k + -2k = 6 + 2k + -2k

Combine like terms: -2k + -2k = -4k
-6 + -4k = 6 + 2k + -2k

Combine like terms: 2k + -2k = 0
-6 + -4k = 6 + 0
-6 + -4k = 6

Add '6' to each side of the equation.
-6 + 6 + -4k = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -4k = 6 + 6
-4k = 6 + 6

Combine like terms: 6 + 6 = 12
-4k = 12

Divide each side by '-4'.
k = -3

Simplifying
k = -3